Uruguay: 1 peso 1994, km103.1, bold and fine writing [opgelost]

https://en.numista.com/catalogue/pieces1096.html

In my CR I've just added in the comments, that there are 2 varieties

Ole

Hello Ole:

For your info, same happens to $ 2 1994 issue and $ 5 2003 issue.

Citeer: "adanieluy"​Hello Ole:
​
​For your info, same happens to $ 2 1994 issue and $ 5 2003 issue.

​

I know, but thanks for the reminder. I don't have the TWO 5 pesos coins, so I haven't documented it yet. If you have high resolution images of the two coins I'll set it up (and of course you'll be mentioned!)?

Ole

Update:

ALL 2003 $5 coins are granulated, only $1 and $ 2 from 1994 are both plain and granulated.

Citeer: "adanieluy"​Update:
​
​ALL 2003 $5 coins are granulated, only $1 and $ 2 from 1994 are both plain and granulated.

​Thanks, that explains why I only have the 2003 in granulated, so no documentation is needed...

Ole

There are 10 types of people, those who understand binary, and those who doesn't.


On your 10 fingers you can count up to what number?



Ole

Citeer: "Sjoelund"​There are 10 types of people, those who understand binary, and those who doesn't.
​
​
​On your 10 fingers you can count up to what number?
​
​
​
​Ole

​I have 1010 fingers (binary base) or 10 fingers (decimal base), so I can count: 1, 10, 11, 100, 101, 110, 111, 1000, 1001 and 1010.

1st 0 or 1
2nd finger 0 or 2
3rd finger 0 or 4
Etc
10th finger 0 or 512!

All fingers up is then?

Citeer: "Sjoelund"​1st 0 or 1
​2nd finger 0 or 2
​3rd finger 0 or 4
​Etc
​10th finger 0 or 512!
​
​All fingers up is then?

​U mean all fingers up= 1111111111 on binary? that means 1023 in dec. base.
You can find it by adding all potences of 2 from 1st. to 10th. ( 1 + 2 + 4 + 8 + 16 + 32 + 64 + 128 + 256 + 512), or the short way is the 11th potence minus 1 (1024-1). (I love maths)

Citeer: "adanieluy"​

Citeer: "Sjoelund"​1st 0 or 1
​​2nd finger 0 or 2
​​3rd finger 0 or 4
​​Etc
​​10th finger 0 or 512!
​​
​​All fingers up is then?

​​U mean all fingers up= 1111111111 on binary? that means 1023 in dec. base.
​You can find it by adding all potences of 2 from 1st. to 10th. ( 1 + 2 + 4 + 8 + 16 + 32 + 64 + 128 + 256 + 512), or the short way is the 11th potence minus 1 (1024-1). (I love maths)
​

​Bravo, you got it.

Ole